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Refactor: Extract common logic from stripOuterParentheses functions
Co-authored-by: warkanum <208308+warkanum@users.noreply.github.com>
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@@ -234,44 +234,26 @@ func stripOuterParentheses(s string) string {
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s = strings.TrimSpace(s)
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for {
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if len(s) < 2 || s[0] != '(' || s[len(s)-1] != ')' {
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stripped, wasStripped := stripOneMatchingOuterParen(s)
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if !wasStripped {
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return s
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}
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// Check if these parentheses match (i.e., they're the outermost pair)
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depth := 0
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matched := false
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for i := 0; i < len(s); i++ {
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switch s[i] {
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case '(':
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depth++
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case ')':
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depth--
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if depth == 0 && i == len(s)-1 {
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matched = true
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} else if depth == 0 {
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// Found a closing paren before the end, so outer parens don't match
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return s
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}
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}
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}
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if !matched {
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return s
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}
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// Strip the outer parentheses and continue
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s = strings.TrimSpace(s[1 : len(s)-1])
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s = stripped
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}
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}
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// stripOneOuterParentheses removes only one level of matching outer parentheses from a string
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// Unlike stripOuterParentheses, this only strips once, preserving nested parentheses
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func stripOneOuterParentheses(s string) string {
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s = strings.TrimSpace(s)
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stripped, _ := stripOneMatchingOuterParen(strings.TrimSpace(s))
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return stripped
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}
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// stripOneMatchingOuterParen is a helper that strips one matching pair of outer parentheses
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// Returns the stripped string and a boolean indicating if stripping occurred
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func stripOneMatchingOuterParen(s string) (string, bool) {
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if len(s) < 2 || s[0] != '(' || s[len(s)-1] != ')' {
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return s
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return s, false
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}
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// Check if these parentheses match (i.e., they're the outermost pair)
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@@ -287,17 +269,17 @@ func stripOneOuterParentheses(s string) string {
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matched = true
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} else if depth == 0 {
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// Found a closing paren before the end, so outer parens don't match
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return s
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return s, false
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}
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}
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}
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if !matched {
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return s
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return s, false
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}
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// Strip only the outer parentheses
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return strings.TrimSpace(s[1 : len(s)-1])
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// Strip the outer parentheses
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return strings.TrimSpace(s[1 : len(s)-1]), true
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}
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// splitByAND splits a WHERE clause by AND operators (case-insensitive)
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